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      Note for the P versus NP Problem

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      Complexity classes, boolean formula, graph, completeness, polynomial time
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            Revision notes

            Sergi Simon detected an error in a single sentence related to the definition of the K-CLOSURE problem. We think this current version is good enough this time.

            Abstract

            Content

            Author and article information

            Journal
            ScienceOpen Preprints
            ScienceOpen
            20 April 2024
            Affiliations
            [1 ] GROUPS PLUS TOURS INC., 9611 Fontainebleau Blvd, Miami, FL, 33172, USA;
            Author notes
            Author information
            https://orcid.org/0000-0001-8210-4126
            Article
            10.14293/PR2199.000759.v3
            d6a6122f-1ee6-4421-854c-7ac36cacb691

            This work has been published open access under Creative Commons Attribution License CC BY 4.0 , which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. Conditions, terms of use and publishing policy can be found at www.scienceopen.com .

            History
            : 15 March 2024
            Categories

            Data sharing not applicable to this article as no datasets were generated or analysed during the current study.
            Data structures & Algorithms,Theoretical computer science
            boolean formula,completeness,graph,polynomial time,Complexity classes

            References

            1. Fortnow Lance. The status of the P versus NP problem. Communications of the ACM. Vol. 52(9):78–86. 2009. Association for Computing Machinery (ACM). [Cross Ref]

            Comments

            Re-commenting on the latest version:

            Sorry to burst your bubble, but the book you cite is incorrect. Notice that the only source for the claim that K-CLOSURE is NP-complete is a never published private communication. In fact, if K-CLOSURE was actually NP-complete, there would be a much shorter proof that P = NP; just take the empty set of vertices as a solution! If the problem is instead about a non-empty subset of vertices (which the statement doesn't clarify), then it is the same problem as finding the smallest weakly connected component of the directed graph, which would also be a shorter proof.

             

            Amazingly, your thought process seems to be correct, although very informally written. I would recommend reading other math papers and consulting peers to get the right tone. Keep at it!

            2025-03-27 14:54 UTC
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